Question

Question 1 1.5 pts A 56 kg rock climber has positioned himself as shown in the figure (with his hands on one side of a gap and his feet on the other side). Both friction and normal forces act on his hands and feet. The width of the gap, w, is 0.30 m and the climber's center of mass is a horizontal distance d = 0.37 m from the gap. The coefficient of static friction Mi = 0.45 between his hands and the rock and pl2 = 1.0 between his boots and the rock. What is the minimum pull by the hands and push by the feet that will keep the climber stationary? Treat the force exerted by both hands as one force, and that exerted by both boots as a second (single) force. Your answer should be in N, but enter only the numerical part in the box. xw d .com

Answer 1

1 56kg 0.3W; d= 0.37, r=0.45, M-10 - Under equilition Condition, the net force is Along in and sn=0 Fans NhNEN {Fy=0 m - AN+ Ag N = mg Matt - 56 (98) Co.usto - 348.48N = 1318.68