Question

A blue ball is thrown upward with an initial speed of 22.8 m/s, from a height of 0.9 meters above the ground. 2.8 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 12.1 m/s from a height of 29.1 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s 1) What is the speed of the blue ball when it reaches its maximum height? s Submit Your submissions: 0 Computed value: 0 Feedback: Correct Submitted: Tuesday, January 15 at 3:39 PM 2) How long does it take the blue ball to reach its maximum height? 2.3 Your submissions: 23 Computed value: 2.3Submitted: Tuesday, January 15 at 3:40PM Feedback: Correct 3) What is the maximum height the blue ball reaches? 27.40 Your subemissiona: 27.40 Computed value: 27.40 Feedbacki Correct Submitted: Tuesday, January 15 at 3:41 PM
4) What is the height of the red ball 3.64 seconds after the blue ball is thrown? Submit Your submissions: 4.8 X Computed value: 4.8 Submitted: Tuesday, January 15 at 3:44 PM Feedback: 5) How long after the blue ball is thrown are the two balls in the air at the same height? Submit Your submissions: 7.24 Computed value: 7.24 Feedback: Submitted: Tuesday, January 15 at 3:38 PM 6) Which plot correctly shows the velocity of the two balls as a function of time? OA O c 7) Which statement is true about the blue bail after it has reached its maximum height and is falling back down? O The acceleration is positive and it is speeding up O The acceleration is negative and it is speeding up O The acceleration is positive and it is slowing down 0 The acceleration is negative and it is slowing down
Please help with the last few parts
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Answer #1

has heen manat as tbd 29.1 1 l lua ball Se4 red bali 2 8 43 4 se caud a6 t ls ball, ie, t reo ball 3.642084 2 2 Thua |heift는2 as o.ラブ< 20.842 c 二 22-8 15.33- eed in

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