Question

Problem 2 4 kN/m 50 kN m Draw the shear and the moment diagram using the mathematical method. BI 4 m 6 m

Answer 1

Given that The shear and the moment diagram using the mathematical method. Sigma f_x = 0 HA = 0 sigma M_A = 0 R_C times 10 - 50 - 4 times 4/2 = 0 R_c = 50 + 32/10 = 82/10 = 8.2 KN R_c = 8.2 kn \r\n shear force: 0 lessthanorequalto x_1 lessthanorequalto 4 Q_1 (0) = 7.80 Q_1(4) = 7.80 - 4 times 4 = -8.20 SF u lessthanorequalto x_2 < 10 [7.8 times x - 4x^2 = 0 x = 7.8/4 = 1 - 9.5 Q_2 (4) = -8.20 KN Q_2 (10) = -8.20 KN SF = 0] Bendingmomen -0 lessthanorequalto x_1 < 4 m_1 (0) = 7.8 times 0 = 0kN - m m_1 (4) = 7.8 times 4 - 4 times 4 times 2 m_1 (4) = -0.80 m_1 (1 - 95) = 7.8 times 1.95 - 4 times 19.5^2/2 m_1 (1.95) = 7.61 B.M 4 lessthanorequalto x_2 lessthanorequalto 10 m_2 (4) = 50