Question

An alcohol 6. Consider the IR, 'H-NMR and 13C-NMR spectra of the compound with MF: C,H, 0. Identify the structure of the unknown compound. 4 pts MF C7H160 MW 116 *C 72.3 %H 13.9 TS SSTT * TRANSMITTANCE Mass Spec. relati m/z abun 27 29 31 19 42 10 45 18 ze SCI 2870.23 Copyright © 1994 WAVENUMBERS

Answer 1

The question is solved using basic concepts of 1HNMR, 13CNMR.

V DATE: 11 V PAGE NO.: Salution There are option Loption A - In option A there is more than 4 types of carbon Nuclei but in IC NMR we can see only a signal | Also there is one protan at position-5 las mentioned above) but in protan NMR there is no such signal for 1H which gives multiplet. Hence option a is not correct ! Lobtion (B) - L a volo - an option (B) there is triplet hence option (B) is not not 1H which gives correct obtion (c)- singlet but [ It is not of carbon On option (c) there is gH which gives in IHNMR there is net such sigual, drenes correct also there is more than a types Nuclei

1 DATE: PAGE NO.: option (D) IH Szogtlom OH Offion (D18 cououect because- » Ня Maloculas Cosmula = C2H60 # 473 molecular weight = 116 Thou is four types of profano present os at S 0.9 ppm there is total 124 which gives to preotan at position - 2. doublet due ! at sa 3.1ppm them is one protan at position-3 which gives triplet at sy 1.8 ppm there i8 2H which give multiplet as it is protams at position-2 and position-4. at sa 1.4 the alcoholic protan showing in LH NMR.