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X=11
-2q isn’t the same it is +3q
3. 22.3.14 Problem 4 (6 EX): As shown in the figure, point charges are located at 3, 8, and 11 cm along the x-axis. What is the x-component of the force on the charge located at x = ■cm given that q = 0.95 μc in N? Numeric : A numeric value is exp ed and not an expression. Fx 0 10 x (cm) +q t 3 9
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Answer #1

As you know the same charge repels each other so force on q ( x=11 cm) due to 3q and d will be repulsive . means towards right direction ( towards + x axis).

Using coulomb's law and superposition principle

Fx=kq(3q)/r2 +kqq/R2

here q=0.95*10-6 C , k=9*109 , r=3 cm =0.03 m , R=8 cm =0.08 m

Fx =9*109*0.95*10-6*3*0.95*10-6/0.032 +9*109*0.95*10-6*0.95*10-6/0.082

Fx = 27075*10-3+1269.14*10-3

Fx =28344.14*10-3

Fx=28.344 N answer

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