AB3 <-------------> A+3 (aq) + 3 B-(aq) is the solubility equilibria
If solubility =s
AB3 <-------------> A+3 (aq) + 3 B-(aq)
s 0 0 initial concentration
- s 3s equilibrium concntration
given solubility s = 0.0980mol/L
thus
the equilibrium constant , called [Ksp] solubility product
is given by
Ksp = [A+3] [B-]3
= [0.0980] [3x0.0980]3
=2.49x10-3
At 25 °C, only 0.0980 mol of the generic salt AB3 is soluble in 1.00 L...
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At 25 °C only 0.0560 mol of the
generic salt AB2 is soluble in 1.00 L of water. What is the Ksp of
the salt at 25 °C?
At 25 °C only 0.0560 mol of the generic salt AB2 is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C? Number
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