Question

A solution is prepared by dissolving 0.69 mol of MgCl2 in 0.50 kg of water.

A.)How many moles of ions are present in solution? (Express your answer to two significant figures and include the appropriate units)

B.)What is the change in the boiling point of the aqueous solution? (Express your answer using two significant figures)

Answer 1

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a A 0.69 males of My cla - Mg Cl in 0.5kg water Mg 2+ Coy) & a ce Coo) Now so I Mach boom 3 lona Males of ion present = 3 xo.ba - 2.07 moles Any B) AS A To = i X M X kb m= males of solute - Oota - 1.38m Mass of salvent 0.5 KG= 0. 512 °C mi/ - Constant 1 [= vent haff bactos les My Cl2 =3 as 3 con are boomed m=malality b = elevation constant ATO = 3 X 1.38 m x 6.512 °C m - 2012 °C So New boiling pt = 100+20 12 = 1020120