Question

4. A solid sphere of mass 2 ks and radius of 0.2 m starts from rest and rolls down a 3.00- high without slipping. What is the
0 0
Add a comment Improve this question Transcribed image text
Answer #1

RANN Am 7 m= mass of sphere = arg. T= Radius of sphere = 0-2 Total Energy of Sphere Just before it steists . rolling down t

Add a comment
Know the answer?
Add Answer to:
4. A solid sphere of mass 2 ks and radius of 0.2 m starts from rest...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest...

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0∘ incline that is 10.0 m long. Calculate its translational speed when it reaches the bottom. Calculate its rotational speed when it reaches the bottom. What is the ratio of translational to rotational kinetic energy at the bottom?

  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest...

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0∘ incline that is 10.0 m long. Calculate its translational speed when it reaches the bottom. Calculate its rotational speed when it reaches the bottom. What is the ratio of translational to rotational kinetic energy at the bottom?

  • A solid sphere of uniform density starts from rest and rolls without slipping a distance of...

    A solid sphere of uniform density starts from rest and rolls without slipping a distance of d = 2 m down a θ = 20° incline. The sphere has a mass  M = 5.8 kg and a radius R = 0.28 m. 1. Of the total kinetic energy of the sphere, what fraction is translational? KE tran/KEtotal 2)What is the translational kinetic energy of the sphere when it reaches the bottom of the incline? KE tran = 3. What is the...

  • A 4.00 kg solid sphere of radius 5.00 cm starts from rest and rolls without slipping...

    A 4.00 kg solid sphere of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. If the length of the incline is 50.0 cm, then the velocity of the center of mass of the solid sphere at the bottom of the incline is

  • A solid homogeneous sphere of mass M = 1.80 kg is released from rest at the...

    A solid homogeneous sphere of mass M = 1.80 kg is released from rest at the top of an incline of height H=1.33 m and rolls without slipping to the bottom. The ramp is at an angle of θ = 26.9o to the horizontal. Calculate the speed of the sphere's CM at the bottom of the incline. Determine the rotational kinetic energy of the sphere at the bottom of the incline.

  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest...

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0? incline that is 10.0m long. Part A Calculate its translational speed when it reaches the bottom. v= Part B Calculate its rotational speed when it reaches the bottom. Express your answer using three significant figures and include the appropriate units. w = Part C What is the ratio of translational to rotational kinetic energy at the bottom?...

  • A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0° incline that is 10.0 m long.

    A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0° incline that is 10.0 m long.A) Calculate its translational speed when it reaches the bottom.B) Calculate its rotational speed when it reaches the bottom.      C) What is the ratio of translational to rotational kinetic energy at the bottom?        D) Avoid putting in numbers until the end so you can answer: do your...

  • A solid homogeneous sphere of mass M = 4.70 kg is released from rest at the...

    A solid homogeneous sphere of mass M = 4.70 kg is released from rest at the top of an incline of height H=1.21 m and rolls without slipping to the bottom. The ramp is at an angle of θ = 27.7o to the horizontal. a) Calculate the speed of the sphere's CM at the bottom of the incline.​ b) Determine the rotational kinetic energy of the sphere at the bottom of the incline.

  • A 3.0 kg solid sphere (radius = 0.20 m ) is released from rest at the...

    A 3.0 kg solid sphere (radius = 0.20 m ) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is 0.90 m high and 5.5 m long. A.) When the sphere reaches the bottom of the ramp, what is its total kinetic energy? B.) When the sphere reaches the bottom of the ramp, what is its rotational kinetic energy? C.) When the sphere reaches the bottom of the ramp, what is...

  • A solid sphere rolls in released from rest and rolls down an incline plane, which is...

    A solid sphere rolls in released from rest and rolls down an incline plane, which is 2.0 m long and inclined at a 30° angle from the horizontal. (a) Find its speed at the bottom of the incline. (Remember that the kinetic energy in rolling motion is the translational kinetic energy ½ Mv2 of the center, plus the rotational K.E. ½ Iω2 about the center. Also remember that v = ωr if the sphere rolls without slipping.) (b) Find the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT