Consider a uniform electric field in the gap between two oppositely charged plates. A singly charged...

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Consider a uniform electric field in the gap between two oppositely charged plates. A singly charged negative ion of mass, m, enters the field with an initial velocity, v(), straight to the right, as shown in the diagram below. The trajectory of the negative ion is such that it enters from the left side of the gap, near the negative plate, and just barely missing hitting the positive plate as it exits the device, as indicated by the dashed line in the figure. Next, a positively charged ion of the same mass, m, enters the gap near the positive plate with an initial horizontal velocity, v(+). If the positive ion just barely misses hitting the negative plate as it exits the device, what must be the relationship between v(+) and v(-). You may neglect the effect of gravity for this experiment. Vc

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Answer 1

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Electnc force accelerat)m = lwe qE now E mr some u semye m utSome in sotm So bot heel defle in perite somme stmce 2 is also some Seme fo both 七

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Answer 2

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