Question

c. Complete the table to summarize your results for the preparation of copper(II) sulfate solutions. Table 12-3. Preparation of copper|11) sulfate solutions. Amount of Volume of the Volume of the Concentration Volume of (M) CUSO, SH,0 Final Solution Concentrated (ml) Solution (ml) Water (ml) 0.50 497g 20mL 20 m 0.20 20mL 8mL lamL 0.10 20mL 10no L 10mL 0.05 20mL 10m 10m 5. Show the measured values of ST for each of the made Cul solutions along with the corresponding absorbance for each. Table 12-4. %T and absorbance for made Cusolutions. Concentration of the Made Solutions (M) Absorbance 0.05 86. ala 0.10 TO . 1143 0.20 .212 0.50 32. 2 .492 Show the calculations of the absorbance using the measured values of "T: A = a-log(%T) 61.4 86.6%T AL 'A=2-log(..)

Show the calculations of the absorbance using the measured values of %T

Answer 1

more the % Transmittance , lesser will be the absorbance

Absorbance and transmitanle are ratio of itensities, We know Absorbance and Transmittance are Related by a equation, A = log ( 7 ) 0 A is absorbance, T is bansmittance, e log - legrithmic If % Transmittance is known then equation ① can be written as absorbance A = 2-dog (%) - © For %T = 86.6% we get Absorbance, Aons = 2-log (86:6) = 2-1.9375 4005 M 0.062.48 absorbance unit (4.u - For % T = 77% we get Absorbance, Aculem = 2- erg (77) 2 -1.88649 Aolom = 01113509 ALL → - For %T = 61.4% we get Absorbance, Aron = 2-log (6114) = 2-1,788168 [ 16.20 m = 0.2118316 Au FOR %T = 32.2 % we get Absorbance, A =2-log (32.2) = 2 1.507855 0.50M = 0.492144 L » DISOM A Conclusim Absorbance is increasing as concentration ncreasing and "Transmite decreasing. Absorbance of concentration Absorbance a % Transmittance

and more the concentration more will be the absorbance.

we put % transmittance in given relation to get the corresponding absorbance.

Absorbance and transmittance are ratio of intensities We know Absorbance and Transmittance are Related by a equation, A = log ( 7 ) - 0 A is absorbance, T is transmittance, & log-ligrithmic If % Transmittance is known then equation can be written as absorbance A= 2-log (%) - 2 - For %T = 86.6% we get a Absorbance, 9.40.05 = ...0 = 2-log (86:6) 2 - lrg (866) 2 - 1.9375 4.05 0.06248 I absorbance unit (Ah) - For % T = 97% we get ince Aodom = 2-log (77) = 2-1.88649 Ao lom = 0111350g ALL - FOR %T = Absorbance, 61.4% we get 4.20M = 2-log (614) - 2- 1.788168 40.204 = 0.2118316 All - FOR - %T = 32,2 % we get Absorbance AAM = 2 log (32.2) 2- 1.507855 14.som = 0.492144 ] OSOM Au Conclusion Absorbance is increasing as concenpation increasing and Transmittance decreasing. Absorbance of concentration Absorbance I % Transmittance