Question

A standardized test is given to a sixth grade class. Histo deviation of performance may have recently changed. She randomly evidence that the standard deviation of test scores has increa rically, the test scores have had a standard deviation of 21. The believes that the standard sampled 30 students and found a mean of 160 with a standard deviation of 21.3846. Is there sed at the a 0.025 level? Assume the population is normally distributed Step 3 of 5: Determine the value of the test statistic. Round your answer to three decimal places Answer How to e Tables Keypad Previous Step Answers Ho σ 21,1, σ > 21 x2025 = 45.722 Subrnit Answer

Answer 1

answer:

given data,

• the class's is grade is sixth
• the test score of the standard deviation is 21
• these are she is randomly sampled students is 30
• these are she  mean is 160
• these are the standard deviation is 21.3846
• the standard score of the test score is increased alpha is 0.025

the step 3 of 5

to find the value of the test statistic is.....?

• the probability is shown in the below step by step,
• here we need the assumed population normally distribution,
• here we are know as the values is already ,
• now we are know as the formula is \chi2 =(n-1)s2/\sigma2,

$\Rightarrow$the probability of the value of the test statistic chi square is \chi2 =(n-1)s2/\sigma2

$\Rightarrow$now substitute the values is in the above formula

$\Rightarrow$(30-1)*(21.3846/21)^2

$\Rightarrow$(29)*(1.0183)^2.

$\Rightarrow$(29)*1.0369

$\Rightarrow$30.0711

$\Rightarrow$there fore 30.0711

30.0711

NOTE: THE GIVEN INFORMATION BASED THESE ARE THE FAINAL ANSWER IS 30.0711