Question

help with 4 and 5 please

Calculate the followings. (6pts) 4. a) The empirical formula for a compound, copper sulfide Cu,S meompound 0.4907 g meopper 0.3923 g (A.- 63.55 g/mol) mufur0.0984g (A.- 32.06 g/mol) O.8o5989motes 63.55 O.0969 0.005061es o.4961 b) The % composition of copper in the compound. 79.95%)S COpper 60 04 903 Balance the following chemical equations. (4pts) S (6) 5 S(s) 2 Cu (s)+ SO2(g) ACuos) + Cu S (s)+202(g)

Answer 1

w moles of Cu ; Amount of cu molas mass cu 0.3923 63.55 0.00617 moles of g : 0.0984 32.06 = 0.00306 cu : 0.00617 S: 0.00306 Now divide the number of moles of each by the smallest no. of moles. S: 0.00306 Gu: : 0.00617 0.00306 S000306 : 2.01 5 = 1 I Gura :: Empirical formula : Guys b) 4. compoginon of Gu = 0.3923 0.3923+0.0984^ = 79.94 .). Of Gu en X 100 5) 260 15) + 565) — Cu2S (5) Cuq sis) + 20219) ► 2010 (9) + 50219)