Question

answer please

192WLCdhuckleb 1: Spring-2019-PHYS-17200-Lectures/ HWO6 Extra 3.10.03 Consider the head-on collision of two identical bowling balls, each with mass 5.0 kg (see figure). Ball A with velocity V-<9, o, o> m/s strikes ball B, which was at rest. Then ball A stops and ball B moves with the same velocity V that ball A had initially. m/s Initially at rest Initial state (before collision) Final state (after collision) Now at rest (a) Choose a system consisting only of ball A. What is the momentum change of the system during the collision? 1) kg·m/s What is the momentum change of the surroundings? Δ p surroundings _ < s > kg-m/s (b) Choose a system consisting only of ball B. What is the momentum change of the system during the collision? -system = < > kg-m/s & P What is the momentum change of the surroundings? AP surroundings (c) Choose a system consisting of both balls. What is the momentum change of the system during the collision? 12 > kg-m/s is > kg-m/s system-: < Tiffa

Answer 1

a) When considering only the ball A, it comes to rest after the collision. so its change in velocity is given by

$\Delta v=<(0-9),(0-0),(0-0)>\: =\: <-9,0,0>$

so the corresponding change in momentum is

$\Delta p=<-45,0,0>$

The change in momentum of the surroundings is

$\Delta p=<45,0,0>$ as the total momentum should always be conserved.

b)considering a system with only ball B,

during collision, the ball attains velocity and the change in momentum is given as the negative of change in momentum of the ball A

$\Delta p=<45,0,0>$

and the change in momentum of the surrounding is

$\Delta p=<-45,0,0>$

c) in a system with both the particles, the total momentum should be conserved. that mean there should not be any change in momentum, before and after collision. So $\Delta p=<0,0,0>$