Question

Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H,0). What is the theoretical yield of water formed from the reaction of 33.9 g of hydrochloric acid and 30.1 g of sodium hydroxide? Round your answer to 3 significant figures. x s ?

Answer 1

glamol NaOH (s) + Hellag) → Nallag) + H2O(l): moles of the mass -33.9 g = 0.929 mola molar man 3 imples of NaOH = 30.1% = 0.753.mol, yog/mol I so, moles of Naoh reacting = moles of Hill reacting then, Nooh is limiting reactant. By osan, Imole Noon forms = 1 mole H₂O 0.753 mol NooH forms = 0.753 mol H₂O Now, mass= moles x molar man of H₂O = 0.753 mol x 18 g/mol = 13.559 -113.68% theosetical yield 1