![Calculate the molar solubility of sp Ksp - [A][cr] spol.sro - AgClass - Agrags + CI Tags huoco Top=s 5 = 1.347105 AgCl(s) in](http://img.homeworklib.com/questions/367b35e0-6f97-11ea-a26e-bb08b6ccc076.png?x-oss-process=image/resize,w_560)
Homework Answers
a)
in pure water ,
solubility of AgCl =1.34 x 10^-5
in common ion (NaCl) ;
solubility of AgCl = 1.8 x 10^-8
so from these calculations ,
molar solubilty of AgCl decrease in common ion.
in presence of common ion , solubility is decreases.
![Ksp of caf, - 3.9x10 2+ + 2 (aq) CaFyrs) ca cag) + 1 s e 0.00125 Ksp = [ca?+][F]? 3.9x16 = Sx (0.00125) s=2.50x10 -5 Solubi](http://img.homeworklib.com/questions/370b6b60-6f97-11ea-864f-e19ae5ca72a9.png?x-oss-process=image/resize,w_560)
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Calculate the molar solubility of sp Ksp - [A"][cr] spol.sro - AgClass - Agrags + CI...
Complete Table 1: Ksp data Salt [cation] (M) [anion] (M) molar solubility (M) Ksp AgCl SrSO4...
Complete Table 1:
Ksp data
Salt
[cation] (M)
[anion] (M)
molar solubility (M)
Ksp
AgCl
SrSO4
Ag2CO3
Sr(IO3)2
1) Rank the salts in order of increasing molar solubility.
2) Rank the salts in order of increasing Ksp
(remember 10–10 < 10–5)
3) If these rankings are not in the same order, why might
Ksp not always scale directly with molar solubility?
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calculate the molar solubility of Cr(OH)3 in a solution with a pH of 11.5 knowing that...
calculate the molar solubility of Cr(OH)3 in a
solution with a pH of 11.5 knowing that Ksp(Cr(OH)3) = 6.7 x
10^(-31)
1. Calculate the molar solubility of Cr(OH), in a solution with a pH of 11.5 knowing that Kop(Cr(OH)2) = 6.7 x 10" 2. What is the pH of a 0.895M sodium fluoride (NaF) solution knowing that the hydrofluoric acid is 7.11 x 10 of 3. Calculate the molar solubility of antimony sulfide (Sb2S) in water knowing K =1.6 x...
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(aq) (1) Mg(OH)2 is partially dissolved in water: Mg(OH), (s) = Mg2+ (aq) + 2OH Write the Kop expression for Mg(OH)2 : Kp = (2) Solid AgCl is partially dissolved in water: AgCl 2 Ag+ + CI''. If the molar solubility is known as [Ag +) = [CI''] = 1.3x 10 M, AgCl Kip =- (a) 1.3 x 10 (b) 1.69 x 10-10 (c) 2.6 x 10 (d) none of these (3) At 25 °C, the solubility of solid AgCl...
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II Review | Constants | Periodic Table Use the Ksp values to calculate the molar solubility of each of the following co...
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[References) Calculate the molar solubility of Ag, SO4 in pure water. Ksp (Ag, 504) = 1.7 x 10-5 Molar solubility = 1 mol/L Calculate the molar solubility of Ag, SO4 in 0.022MAgNO3. Molar solubility = mol/L Calculate the molar solubility of Ag, SO4 in 0.022MK2SO4. Molar solubility = mol/L APPENDIX Solubility Product Constants for Some Inorganic Compounds at 25°C Substance K Substance 1.6 x 10-16 1.9 X 10-33 1.3 x 10-30 7.8 x 10-21 6.7 X 10-11 24 X 10-...
Complete Table 1:
Ksp data
Salt
[cation] (M)
[anion] (M)
molar solubility (M)
Ksp
AgCl
SrSO4
Ag2CO3
Sr(IO3)2
1) Rank the salts in order of increasing molar solubility.
2) Rank the salts in order of increasing Ksp
(remember 10–10 < 10–5)
3) If these rankings are not in the same order, why might
Ksp not always scale directly with molar solubility?
Design experiments in the virtual lab to answer the follow questions, 1). Use the virtual lab to determine the...
Calculate the solubility product constant, Ksp, for Chromium(III) Hydroxide (Cr(OH)3) which has a solubility of 1.27 x 10-6g/L. 7.0 x 10-23 6.3x10-31 1.87 x 10-24 2.31 x 10-32 3.6 x 10-31 How is the molar solubility (s) of Tin(II) hydroxide related to Ksp? s = (Ksp) 1/2 s-(Ksp/4)1/3 s = (Ksp/108)1/5 s = (Ksp/9)1/3 s = (Ksp/27)1/4 Calculate the concentration of OH ions in a saturated solution of Manganese (1) hydroxide, Mn(OH)2 Ksp for Mn(OH)2 = 4.6 x 10-14 (Report...
calculate the molar solubility of Cr(OH)3 in a
solution with a pH of 11.5 knowing that Ksp(Cr(OH)3) = 6.7 x
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1. Calculate the molar solubility of Cr(OH), in a solution with a pH of 11.5 knowing that Kop(Cr(OH)2) = 6.7 x 10" 2. What is the pH of a 0.895M sodium fluoride (NaF) solution knowing that the hydrofluoric acid is 7.11 x 10 of 3. Calculate the molar solubility of antimony sulfide (Sb2S) in water knowing K =1.6 x...
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