Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected...
Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected in series to a 12.0-V battery, the current from the battery is 1.77 A. When the resistors are connected in parallel to the battery, the total current from the battery is 11.3 A. Determine the two resistances.
Homework Answers
When connected in series
R1 + R2 = V/I = 12/1.77
R1 + R2 = 6.78
R1 = 6.78 - R2 .. (I)
When connected in parallel
R1 * R2/ ( R1 + R2) = 12/ 11.3
From (I)
(6.78 - R2 ) * R2 = 1.06 * ( 6.78)
6.78R2 - R2^2 = 7.19
R2^2 - 6.78R2 + 7.19 = 0
R2 = 5.46 ohm (Ans)
From (I)
R1 = 6.78 - 5.46 = 1.32 ohm (Ans)
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