Question

A 15 kg uniform beam, 2 m in length, is supported at it's end by a cable as shown below. The angle between the cable and the horizontal is 45 degrees. 2. Cable Beam Find the horizontal and vertical components of the force from the hinge (left end of the beam) acting on the beam a. b. If the tension in the cord exceeds 115N, the cord will break. Will placing a 5 kg mass at the right end of the beam break the cord? Show your work that justifies your answer below. F m

Answer 1

Sigma T = 0 = T sin theta(1/2) - mg(1/2) = 0 T = mg L/2 C (sin theta) T = 15 times 9.8/2 sin(4.5 = 103.95 N a) horizontal R times T cos theta = 103.95 times cos 45 R_x = 73.5 N vertical (R_y) = T sin theta - MG = 103.95 times sin 45 - 15 times 9.8 R_y = -73.5 N b) sigma T = (T sin theta L) - MG(L/2) - mg(L) = (1150 d sin 45 times 2 - 15 times 9.8 times 2/2 - 5 times 9.8 times 2 tau = -82 4 N.m since torque is negative the cord will break if we place 5 kg at end