Homework Answers
Given:
Energy of 1 mol = 2.39*10^2 KJ/mol
= 2.39*10^5 J/mol
Find energy of 1 photon first
Energy of 1 photon = energy of 1 mol/Avogadro's number
= 2.39*10^5/(6.022*10^23)
= 3.969*10^-19 J
This is energy of 1 photon
use:
E = h*c/lambda
3.969*10^-19J =(6.626*10^-34 J.s)*(3.0*10^8 m/s)/lambda
lambda = 5.01*10^-7 m
lambda = 501 nm
Answer: 501 nm
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