| Person | Xi | Yi | Xi +Yi | XiYi |
| 1 | 6 | 9 | 15 | 54 |
| 2 | 4 | 5 | 9 | 20 |
| 3 | 6 | 3 | 9 | 18 |
| 4 | 0 | 7 | 7 | 0 |
| 5 | 7 | 8 | 15 | 56 |
| Total | 23 | 32 | 55 | 148 |
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9. Given the following data, determine the nu- merical value of each of the expressions below....
9. Given the following data, determine the nu- merical value of each of the expressions below. Person (i) X, 610 99/ 4 5 25 4 0 7 49 749 8 i.ΣΧ Xi 10. Given the data from Exercise 9 for X and Yan that c, a constant, equals 3, determine the nu merical value for the following expressions:
I need help with 3,4,5.
Solve for the expressions below given that Xi = 9, x2-6, x3--2, and X4-4: i=1 2)y = 137 i=1 2 示 :1 4.) Σ(xi-x) = i=1 5) Σ(xi-x)2 =
Using the data table below, calculate the values for the following expressions. Note that n represents the number of summations (i.e. when calculating Xx;, then n=3). X and are the means of the values being summed (i.e. when calculating 2x;, then X = [*;, then X = X,+X.). Record all answers in the Part IV worksheet of the Assignment 1 spreadsheet. (Each calculation is worth 2 marks). 1 2 4 5 6 7 3 22 х 14 19 35 16...
Solve for the expressions below given that Xi = 9, x2 = 6, x3 =-2, and X4-4: 6.) Sample Variance - に1 2 7) Sample Variance: Xi i=1 t T. y- 8.) Sample Standard Deviation = 年:美 2 飆 %) Sample Standard Deviation = n- 1 i=1
1· (1 point each) Given the array defined below, evaluate each of the expressions and write their value in the space provided. If the expression will cause an error, write "ERROR" in the space instead. Note that each expression is independent. They do not build on each other, so each should be applied to the original array as shown here: int [ ] numbers = {7, 15, 13, 10): a. numbers[O] b. numbers[2] c. numbers[1 + 2] d. numbers[4] e....
the equilibrium constant is given for two of the reactions below. Determine the value of the missing 23) - equilibrium constant A(g) +B(g) - AB(g) AB(g) + A(g) - A2B(g) 2 A(g) +B(g) - A2B(g) Ke=0.24 Ke = 3.8 Ke=? A) 0.63 B) 4.0 C) 16 D) 0.91 E) 3.6 24) 24) Determine the value of Kp for the following reaction, at 300K, if the equilibrium concentrations are as follows: (N2leq -1.5M, [H2leq = 1.1 M, (NH3 leq = 0.47...
9) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. 104 H2(g) + Br2(8) = 2 HBr(g) 2 HBr(g) = H2(g) + Bra(8) Ke3.8 Ke=? A) 1.9 x 104 B) 5.3 x 10-5 C) 2.6 x 10-5 D) 6.4 x 10-4 E) 1.6 % 103 Answer: C Diff:2 Var: 1 Global: G4 LO: 14.3 Page Ref: 14.3
A-D
9. Use the data given below for the following reaction at 25 C. Fe 04 (s)+ 4 H2(g) 3 Fe (s) + 4 H2O (1), (12+4+4+10-30) Fe Oa(S) 146.4 APH (kJ/mol) -1118.4 H:(g) 130.6 H2O(I) Fe(s) 27.28 S' (J/K/mol) 69.61 -285.83 0 (5+5+2+5=12) (a) Calculate AS,ys, AS,urr, ASuniy and AG at 25°C. ASy's Hh 172 (b) Is the reaction spontaneous at 25°C from entropic point of view? (4) (c) Is the reaction spontaneous at 25°C from free energy point...
Problem 9-14 Given the following activity times in months, determine the items listed below: Time Estimates (months) Activity Activity Predecessor а т 4 12 A B 6 10 15 С 2 10 14 1 D A 4 13 E A 3 F В 3 6 18 G 2 8 12 Н С.Е.F С.Е.F 15 22 I 5 12 21 J D 20 25 K G.I 5 12 L Н.К 3 20 Expected activity times b. Variance times а. c. Earliest...
Q.1)) (12.5 marks) Given the values below, what is the value of each of the following expressions (0 or 1)? INTEGER :: age=34, old=92, young=16 1. age /= old 2- (age==56.AND. old/=92) 3- (age--56.OR. old/=92) 4- (age==56.OR. (.NOT.(old/=92))) 5-.NOT. (age==56.OR. old=92) 6- (young<old).NEQ.(young>=16) 7- young age<old 8-.NOT.(young/=old) (125 marke