20. A 2.00x102-g sample of water at 60.0°C is heated to steam at 140.0°C. How much...

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Question

science physics

Answer 1

Answer #1

m= 200gm = 0.2Kg

S(water) =4185.5 J/kg/K

L(vaporization) =2260000 J/Kg

S(steam) =1996 J/ kg/K

T1= 60C

T2=140C

H = mS(water)*(100-T1)+mL+ mS(steam) *(T2-100)

=5014520.8J

=501.45 KJ

Answer 2

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