Question

We are to use excel.

ne inhibitor, while likely to resemble? 60. MATHEMATICAL Draw Lineweaver-Burk pl ts for the behav- mental data are me for which the following experimental available. [S] V, No Inhibitor (mmol min) V, Inhibitor Present (mmol min-1) (mm) 8.0 iadur 5.0 4.58 6.40 7.72 8.72 9.50 3.66 5.12 6.18 6.98 7.60 9.0 11.0 are the Ky and Vmax values for the inhibited and unin ited reactions? Is the inhibitor competitive or noncomp e or noncompetitive?

Answer 1

There is a Michaelis-Menten enzyme. I need a Linewaver-Burk graph in which x axis is 1/[S] and y axis is 1/V. The graph will be doing in exel2007

[S] (mm) 1/15 mm V (mmol/min) no inhibitor 1/V (min/mmol) no inhibitor V(mmol/min) inhibitor present 1/V(min/mmol) inhibitor present 3,0 7,0 0,3333| 0,2000 0,1429 0,1111 0,0909 4,58 6,40 7,72 8,72 9,50 0,2183 0,1563 0,1295 0,1147 0,1053 3,66 5,12 6,18 6,98 7,60 0,2732 0,1953 0,1618 0,1433 0,1316 9,0 11,01 0,3000 0,2800 y = 0,5846x + 0,0784 R2 = 1 0,2600 0,2400 0,2200 1/V (min/mmol) 50,2000 No inhibitor inhibitor present Lineal (inhibitor present) Lineal (No inhibitor) 30,1800 y = 0,4665x+0,0629 R2-1 0,1600 0,1400 0,1200 0,1000 0,0500 0 ,1000 0,15000 ,2000 1/[S] mM-1 0,2500 0,3000 0,3500 NL - - - - -

The next step is to calculate K_M without inhibitor and K_Mapp with inhibitor and V_max without inhibitor and with inhibitor to identify what kind of inhibition the enzyme has.

In the regresion curve y=ax+b, b is the upper ratio rate (V_max) and a is K_M/V_max.

With inhibitor the upper ratio rate is

$\frac{1}{V_{max,app}}=0.0784\frac{min}{mmol}$

$V_{max,app}=\frac{1}{0.0784\frac{min}{mmol}}=12.7551\frac{mmol}{min}$

The K_M,app is:

$K_{M,app}*0.0748\frac{min}{mmol}=0.5846\frac{min}{l}$

K_M,app=7.8155mM

K_M units are:

mmol עעעעעעעעעעעעעעע

Without inhibitor, the upper ratio is:

$\frac{1}{V_{max}}=0.0629\frac{min}{mmol}$

$V_{max}=\frac{1}{0.0629\frac{min}{mmol}}=15.8983\frac{mmol}{min}$

But K_M is calculated by:

$K_{M}*0.0629\frac{min}{mmol}=0.4665\frac{min}{l}$

$K_{M}=7.4165mM$

The inhibition is noncompetitive because it reduces V_max and K_M.