143 lb and a standard deviation given by 25 Suppose that the weights of women marathon...

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Question

math Statistics-And-Probability

Answer 1

Answer #1

Given that, mean (μ) = 143 lb and

standard deviation $(\sigma)$ = 29 lb

a) We want to find, P(X > 157)

P(X > 157) X-4 157 – 143 29 = P(Z > 0.48) = 1- P(Z < 0.48) =1-0.6844 = 0.3156

Therefore, required probability is 0.32

b) sample size (n) = 4

We want to find, PT> 157)

P(X > 157) = PA-1. 157 - 143 FC = P(Z > 0.97) = 1 - P(Z < 0.97) = 1 - 0.8340 = 0.1660

Therefore, required probability is 0.17

Answer 2

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