Question

(3 pt.) 5. Listed below are the ages of randomly selected race car drivers. of randomly selected race car drivers. Construct

0 0
Add a comment Improve this question Transcribed image text
Answer #1

X 32 X - mean -1.6 32 -1.6 -0.6 33 33 41 -0.6 7.4 -4.6 4.4 29 38 (X-mean) 2 2.56 2.56 0.36 0.36 54.76 21.16 19.36 2.56 0.36 1
Since we know that
Mean() - Σ1 ;
Where n is the number of data points
Now
Στη = 504.0 1-1
and n = 15
This implies that
504.0 Mean(T) = 15 Mean(T) = 33.6
Since we know that
Variance(82) – Eti – 7)? -1 n Sri – 7)2 = 823.6 n = 15 Variance(52) - 823.6 Variance(s?) = 58.8286 Standard Deviation(s) = V

Mean (\bar{x}) = 33.6
Sample size (n) = 15
Standard deviation (s) = 7.67
Confidence interval(in %) = 98
ta/2.n-1 = 2.624
Since we know that
Confidence interval = ī ta/2,1–17
Required confidence interval = (33.6 – 2.624.07, 33.6 +2.6247.07 V15 V15
Required confidence interval = (33.6-5.1965, 33.6+5.1965)
Required confidence interval = (28.4035, 38.7965)
Please hit thumps up if the answer helped you.

Add a comment
Know the answer?
Add Answer to:
(3 pt.) 5. Listed below are the ages of randomly selected race car drivers. of randomly...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • please break down the problem (3 pt.) 5. Listed below are the ages of randomly selected...

    please break down the problem (3 pt.) 5. Listed below are the ages of randomly selected race car driver confidence interval estimate of the mean age of all race car drivers. normally distributed. cted race car drivers. Construct a 98% face car drivers. Assume that this data is 32 32 33 33 41 29 38 32 33 23 27 45 52 29 25

  • 33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected...

    33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected customers found the ages shown (in years). The mean is 31.76 years and the standard deviation is 10.37 years. a) Construct a 98 % confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 20 38 40 35 40 interval have been met. 22 37 10 41 26 b) How large is the margin of error?...

  • A survey of 25 randomly selected customers found the ages shown (in years). The mean is...

    A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.28 years and the standard deviation is 9.35 31 21 44 32 34 11 48 42 23 45 39 35 31 28 29 43 34 37 20 44 33 27 24 a) Construct a 80% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of...

  • Do the Academy Awards involve discrimination based on age? Listed below are the ages of actresses...

    Do the Academy Awards involve discrimination based on age? Listed below are the ages of actresses and actors at the times that they won Oscars in the Best Actress and Best Actor categories. the ages are listed in order, beginning with the first Academy Awards ceremony in 1928. (Note: in 1968 there was a tie in the Best Actress category, and the mean of the two ages is used; in 1932 there was a tie in the Best Actor category,...

  • Among drivers who have had a car crash in the last year, 250 were randomly selected and categorized by age, with the res...

    Among drivers who have had a car crash in the last year, 250 were randomly selected and categorized by age, with the results listed in the table below. Age Under 25 25-44 45-64 Over 64 Drivers 98 56 38 58 If all ages have the same crash rate, we would expect (because of the age distribution of licensed drivers) the given categories to have 16%, 44%, 27%, 13% of the subjects, respectively. At the 0.025 significance level, test the claim...

  • A survey of 25 randomly selected customers found the ages shown? (in years). The mean is...

    A survey of 25 randomly selected customers found the ages shown? (in years). The mean is 33.16 years and the standard deviation is 9.21 years. 47 35 45 21 30 42 49 29 28 35 27 29 45 35 11 34 28 33 44 39 34 25 34 32 18 a) What is the 90% confidence interval for the mean age of all customers assuming that the assumptions and conditions for the confidence interval have been met? b) What is...

  • Inferences from Two Samples chapter Listed below are the ages of actresses the awards ceremony, b...

    Inferences from Two Samples chapter Listed below are the ages of actresses the awards ceremony, but the ages in and actors at the times that they won the table below are based on the birth Oscars for the categories of Best Actress date of the winner and the date of the and Best Actor. The ages aze listed in awards certmony) chronological otder by row, so that cor- responding locations in the two tables Analyzing the Results are from the...

  • The utility bills (in dollars) of 10 randomly selected homeowners in one city are listed below....

    The utility bills (in dollars) of 10 randomly selected homeowners in one city are listed below. Construct a 95% confidence interval for the mean. Assume the population is normally distributed. 70, 72, 71, 70, 69, 73, 69, 68, 70, 78 (68.95, 73.05) (69.00, 78.00) (70.05, 72.95) (68.13, 73.87) Suppose a 98% confidence interval for μ turns out to be (1000, 2100). If this interval was based on a sample of size n = 22, find the value of the margin...

  • A survey of 25 randomly selected customers found the ages shown (in years). The mean is...

    A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.60 years and the standard deviation is 9.52 years a) Construct a 90% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?...

  • The U.S. Census Bureau collects data on the ages of married people. Suppose that eight married...

    The U.S. Census Bureau collects data on the ages of married people. Suppose that eight married couples are randomly selected and have the ages given in the following table. Determine the 90% confidence interval for the true mean difference between the ages of married males and married females. Let d=(age of husband)−(age of wife). Assume that the ages are normally distributed for the populations of both husbands and wives in the U.S.: Husband: 75 41 62 38 53 27 59...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT