3. (4 pts) A pH of 0.002 M solution of monoprotic acid is 3.5. Find dissociation...

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science chemistry

Answer 1

Answer #1

P Let HA is the acid HA - H+ (aq) & Ă (aq) Initially. 0.002 at eab (0.002-x) x x Given pH = -log[++] = 3.5 [24+] = 3.16x10m [

Answer 2

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