Question

1. Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction: 2Na (s) 3N2 (g) 2NAN3 (s) 72.01 IL1,01(3) What mass of NaN3 (s) must be reacted to inflate an air bag to 70.0 L at 1 atm and 20°C? (8 pts.) 1273,15 293.15 21100,8 0V mol HOTS 3,31 X10 2. Exactly 50.0 mL liquid methanol (CH3OH, density 0.850 g/mL) and 22.8 L O2 gas reacted at 27°C and a pressure of 2.00 atm to form CO2 and H20 as shown below.. What is the maximum number of moles of H2O that can be formed from the reaction? (10 pts.) (00:HC 2CH3OH (I) +302 (g) 2CO2 (g) + 4H2O (g)

Answer 1

& 9 beiven recach is 2Nang(s) - 2 Nais! + 3 N2 (9) • volumell)= 7ot Temp. (T)= 20°c = 293k Pressene (P) = Sahn PV, Go T a. Now male of Na N3 (2) 127 0.08206 Lahm x 293k 1 molk - n = 2.92 mal So Required mass = n xMola May = 2.92 mol x 659) om = 189.2497 ② Criven reach is 2CH2OH() +30219) — 26, 19) +4 #0 (9) volume of Chzon = som сему ч ) си,ои = 0- Yws/mk * Ким е , он : Vokru x оfevr'я > Фm Lх о• {\va m=42.59 Now, Volume of Oz (Voz )= 22.86 male of Ctgoh 2 42.59 . 32g/mas Temp. (T)=300k Prensene = zahn No, pa zahm x 22.8 L = 1.86 ml 0.0 82.06 Lahin x 3008 Alreac" 2 mole of CHq OH recact with 3 male of a 1:39 mole of Cf yok eceact with (3 x 1:33) male of a a 2 mole of O2 Beef we have so O ei limiting reagent Aloccac" 3 mole of a forodluce uncle of the 1086 ! " 1.86mal, only on = 12:48moll