Question

A Review | Constants | Periodic Table You place 1.45 mol of NOCl(g) in a reaction vessel. Equilibrium at constant pressure is established with respect to the decomposition reaction Part C Calculate NOCI(8) = NO(g) + Cl2 (8) AGE and the degree of dissociation of NOCl in the limit that is very small at 350. K and a pressure of 1.50 bar. AH Substance (kJ · mol-1)(298 K) (kJ. mol-1)(298 K) NOCI(g) 51.7 66.1 NO(g) 91.3 87.6 Cl2 (g) 0 0 Express your answers using three significant figures separated by a comma. VACO R O P ? Ć, B = Submit Request Answer

Answer 1

$\xi$ = $\Delta$H^o_reaction - $\Delta$G^o_reaction

Here, $\Delta$G^o_reaction = $\Delta$G^o_NO - $\Delta$G^o_NOCl = 87.6-66.1 = 21.5 kJ/mol

And $\Delta$H^o_reaction = $\Delta$H^o_NO - $\Delta$H^o_NOCl = 91.3-51.7 = 39.6 kJ/mol

Now, $\xi$ = 39.6 - 21.5 = 18.1

And Degree of dissociation of NOCl = $\Delta$G^o_reaction/$\Delta$H^o_reaction = 21.5/39.6 = 0.543