Question

According to the problem;

This pressure decreases by 19.8 mm Hg for every 1000- ft increase in elevation.

Total pressure drop at 1.55*10^4:

19. 8 mm Hg / 1000 ft * 1.55 x10^4 ft = 306.9 mm Hg

The boiling point of water decreases 0.05 C for every 1 mm Hg drop in atmospheric pressure.

Total temperature drop = 0.05 deg C / 1 mm Hg * 306.9 mm Hg = 15.345 deg C

Boiling point = 100 – 15.345 = 84.655 deg C

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