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For the following reaction, 0.362 moles of sulfur dioxide are mixed with 0.328 moles of water sulfur dioxide(g) + water() - s
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Answer #1

50,(8) + Hgoll) → Hys03 (3) - Hq 0.362 mol 0.328 mol H al- = 23.c = 9 from stochiometry molar ratio of so, and H90 és 1:1 cohope you will like my answer .

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