Homework Answers
2H2S(g) + 3O2(g) -----------> 2H2O(l) + 2SO2(g)
H0rxn
=
H0f products -
H0reactants
= 2*-296.83 + 2*-285.83 - (2*-20.63 + 3*0)
= -1124.06KJ/mole
S0rxn
= S0f products - S0f reactants
= 2*248.22+2*69.91 - (2*205.79+ 3*205.138)
= -390.734J/mole-K
= -0.390734KJ/mole-K
T = 25 + 273 = 298K
G0rxn
=
H0 rxn - TS0rxn
= -1124.06-298*-0.390734
= -1007.62KJ/mole >>>>answer
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