Homework Answers
electric potential due to charge = kq/r
where q = charge , r =distance from the charge
electric potential midway = kq1/r1 + kq2/r2
= 9*10^9*10^-6 ( 3.1 / 1.4 - 6.6 / 1.4)
= -22500 V
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Chapter 19, Problem 13 Two point charges, +3.10 HC and -6.60 uC, are separated by 2.80...
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Chapter 19, Problem 13 Two point charges, +2.20 uC and -7.30 uc, are separated by 1.20 m. What is the electric potential midway between them? Number Units the tolerance is +/-2%
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Two point charges, +3.09 uC and -6.25 HC, are separated by 1.32 m. What is the electric potential midway between them?
Chapter 19, Problem 16 GO The drawing shows a square, each side of which has a...
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Two identical point charges (q = +7.00 x 10-6 C) are fixed at opposite corners of...
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Problem A-2.80 HC point charge is fixed at the origin of the x axis. A-7.80 uC...
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Chapter 19, Problem 18 A charge of +213 uC is fixed at the center of a...
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Chapter 19, Problem 13 Two point charges, +2.20 uC and -7.30 uc, are separated by 1.20 m. What is the electric potential midway between them? Number Units the tolerance is +/-2%
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Two point charges, +3.09 uC and -6.25 HC, are separated by 1.32 m. What is the electric potential midway between them?
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Problem A-2.80 HC point charge is fixed at the origin of the x axis. A-7.80 uC point charge of mass 1.50 grams is moving along the r axis from the +x direction toward the charge at the origin. It has a speed of 22.0 m's when it is atx 0.800 m.Ignore gravity. Calculate (a) the total energy of the-780 pC when it is at x-0.800 m. 0.609 J (b) the position along the x axis where the speed of the...
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