Question

4) What volume, in milliliters, of 0.655 M LiCl solution contains 19.6 g of LiCl? 155 M OLIYO

Answer 1

Molar mass of LiCl,

MM = 1*MM(Li) + 1*MM(Cl)

= 1*6.968 + 1*35.45

= 42.418 g/mol

mass(LiCl)= 19.6 g

use:

number of mol of LiCl,

n = mass of LiCl/molar mass of LiCl

=(19.6 g)/(42.42 g/mol)

= 0.4621 mol

use:

M = number of mol / volume in L

0.655 = 0.4621/ volume in L

volume = 0.705 L

volume = 705 mL

Answer: 705 mL