Question

Find the margin of error for the given values of​ c, sigma​, and n. cequals0.90​, sigmaequals2.8​, nequals36

Answer 1

Solution :

Given that,

$\sigma$ = 2.8

n = 36

At 90% confidence level the z is ,

$\alpha$ = 1 - 90% = 1 - 0.90 = 0.10

$\alpha$ / 2 = 0.10 / 2 = 0.05

Z_$\alpha$/2 = Z_0.05 = 1.645

Margin of error = E = Z_$\alpha$/2* ($\sigma$$\sqrt$/n)

= 1.645 * (2.8 / $\sqrt$ 36 )

= 0.8

Margin of error = E = 0.8