Question

need help pleasee problem 10

PB Song & 300g = bonge Total Physics 201 Exam 3 - Page 7 of 7 11/13/19 10. Two chal two children are bollamc da has a mass of 31 miseless fes most Tethe imponan uneven w as shown inh r this mestion we well treat the Child B Mo = ? Child A m = 30 kg M=30kg AX-6.9m AXA=silm (a) (10 points) What is the mass of child b? IMC²=3 & ML" IML2 = 12 ML? LN (69) = 1 (30)(5,2² 30kg 2 + M26.9² = 260,1 M667.6) = 260, M = 116.39 kg (b) (5 points (bonus)) What is the upward force on the seesaw exerted by the support? mgtMg ( ² ) - 1150 C16 XC9.84 349,5/16-2751)-n=0 2058-n=o -2058 2058 In 1924.62N

Answer 1

Cal By Torque balany 30x 98 x 6.9 = mx g8x5:1 me Upward 30.6.673 - 40.59 tong the force on see saw - (6) e. 130+ 40.59 1 a 9.8 e 691.76 N Ans