Question

1and 3 pls

1) A particular coal contains 2.55% sulfur by mass. When the coal is burned, it produces sulfur dioxide emissions, which combine with rainwater to produce sulfuric acid. Determine how much sulfuric acid (in metric tons) is produced by the combustion of 2.0 metric ton of this 15pts coal. 2) A box contains equal amounts of helium, argon, and krypton at 25C. Describe the masses, average velocities, and average kinetic energy of the three kinds of gas in the mixture What do they have in common? What are the differences? 10pts 3) Choose a two sets of quantum numbers (from n=1 to n-5) for an electron of hydrogen atom. Calculate the wavelengths of light produced if an electron moves from one state to two other different states. 10pts

Answer 1

Reactions of sulphur to form sulphuric acid are as follows- S(s) + 0,08) - S02 (8) SO,(-9) + (9) - So (9) 5909) + H2o W → Hz Soya) So from one mole sulphur one mole sulphuric acid is Atomic weight of sulphur is 32 g/mol. Molecular weight of sulphuric acid is 98 g/mol. So from 32 g sulphur 98 g of sulphuric acid is Now the total amount of coal is 2.0 MT. percentage of sulphur in coal is 2.55 % produced. produced. So total amount of sulphur in the sample = 2.0 MT x 2.55 100 = 0.051 MT = 51 kg (as IMT = 1000 (3) 51 x 103 g (as 1 kg = 1039). produces g8 g sulphuric 32 g sulphur So, 51x103 g « acid ” 98 x51x103 g - 156.2 x 103 og = 1562 kg = 0.156 MT. 0.156 MT sulphuric acid is Produced by the noton of B.ONT combuston a herebre, coal.

Let us take the quantum numbers n=1, 2 and 3. We will calculate the wavelengths of light Produced when From n=3 state to n = 2 and n=1 state respectively. We know the Radberg's equation as- an electrons moves + = Ruman) light. where & is the wavelength of the emitting RH is the Rydberg constant and is n, is the lower energy state and 1.09737 x 10 m n is the higher energy state. So, when the electron moves from n=3 to n=2 . Í - 1-09737 X107 mil (2 399 ) 1.09737 x 10 tim = 1.09737 x 107 m x 0.138 3- 2 or 32 30 - 6.561 x 107 m. = 656.1 nm ( nm = 10-9 m). Therefore wavelength of the light when 656.1 nm. the electron moves from n=3 to n=2 is a When the edectron moves from n=3 to n=1, F 1.09737 x 107 m 0 t = 1:09737 x107m' (1-5) ARI = 66 1.025 * 10 = 102.5 nm. Therefore bre, Wavelength of the light when the electron moves from n=3 to n=1 is 102.5 nm.