Question

A gardener pushes a lawn mower a distance of 1500 m mowing a yard. The handle of the mower makes an angle of 30° with the ground. The gardener exerts a force of 30.0 N along the handle of the mower (that is, at the 30° angle with respect to the ground). How much work does the gardener do mowing the lawn?

Answer 1

Work done is force times displacement. In vector form :

$W = \vec{f}.\vec{d}$

$\therefore W = fd cos(\theta)$

Given:

$d = 1500m$

$f = 30.0N$

$\theta= 30\degree$

$\therefore W = (30.0N)(1500m)cos (30\degree)$

$\therefore W = 38971.14 J$ ...(Answer)