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29. The heat of combustion for a given organic molecule was being measured in a bomb calorimeter (heat capacity of 2.24 J/°C)

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This question is solved by using the the simple concept of determination of empirical formula and molecular mass.

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mores 12 Answers Ccal = 2.245/°C AT=4.6°C ти, о : 94vog. On C-85-714. H=14.297. Molesofc = 85.71 – 7.1425 mol MolesqH = 14.29Melecular formula = (Che)n =(CH), = C2H+ (S) Heat released Heat gained =met + Ceal at - 2400X4.18 x406+ 2.24x416 = 46147.2+10

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