Answer
A) - 39.6 J/ mol K
Explanation
Zn(s) + 2HCl(aq) ------> ZnCl2(aq) + H2(g)
∆S°rxn = nS°(products) -
mS°(reactants)
n and m are coefficients of products and reactants
= ( 1 × S°(Zn2+(aq)) + 2 × Cl-(aq)) + 1×S°(H2(g))) - ( 1 × S°(Zn(s)) + 2×S°(HCl(aq)))
= ( 1 × -106.5J/mol K + 2× 55.10J/mol K + 1 × 130.58J/mol K) - ( 1× 60.9J/mol K + 2× 56.5J/mol K)
= 134.28J/mol K - 173.9J /mol K
= -39.6J/mol K
24. Determine A Sºrxn given the following information: Reaction: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(9)...
Determine
S°rxn for Zn (s) + 2HCl (aq)
ZnCl2 (aq) + H2 (g).
Substance
S° (J/mol ⋅ K)
Zn(s)
60.9
HCl(aq)
56.5
H2(g)
130.58
Zn2+(aq)
−106.5
Cl−(aq)
55.10
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