Question

Find a set of coefficients that balance the followi C23H460, + O2 -----> CO + H2CO3 balance the following equation:

Answer 1

O + H₂CO3 80 dae) gruen? C23446 Oz + O2 → co + H₂CO3 To There is only 2 u atoms on right spole while 46 Hatoms on left side. Thus, we put the coefficient 23 (46/2) befoot H₂CO3. Thus, there are 23 catoms on left side as well as right side. Thus, we put on coefficient before con Nowe, we have (23x3=69) o atoms on night spde, but only qo atoms on left side, There is no need of any coeffouent before C2344697. Thus, remaining o atoms = 69-7 = 62 62/2= 31. Thus, we put Coefficant 31 before Oz. Thus, the egn. 6 becomes 623446°7 + 310, >oco + 23H2CO3.