Question

Explain the steps, in detail, for this electric dipole derivation.

all write nus signs, as we commonly the magnitude of the net field at P as do with lUICes aiong E = E(+)- E(-) (22-5) After a little algebra, we can rewrite this equation as (226) After forming a common denominator and multiplying its terms, we come to d (22.7) 2z We are usually interested in the electrical effect of a dipole only at distances that are large compared with the dimensions of the dipole- that is, at distances such that z > d.At such large distances, we have d/2z 1 in Eq.22-7.Thus, in our approx- imation, we can neglect the d/2z term in the denominator, which leaves us with (22-8) 27rEO The product qd, which involves the two intrinsic properties q and d of the ipole, is the magnitude p of a vector quantity known as the electric dipole moment of the dipole. (The unit of p is the coulomb-meter.) Thus, we can write Eq. 22-8 as (22-9) 2me z3 (electric dipole) direction of p is taken to be from the negative to the posius end of the pole, as indicated in Fig. 22-9b. We can use the direction of p specity the rientation of a dipole. Equation 22-9 shows that, if we measure the electric field of a dipole only at r product. The field at distant points would be unchanged if, for example. ints, we can never find q and d separately; instead, we osn find only

Answer 1

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