A 32.4-g ice cube at 0 °C is added to 125 g of water in a 63.3-g aluminum cup. The cup and the water have an initial temperature of 23.0 °C. Calculate the equilibrium temperature of the cup and its contents.Calculate the equilibrium temperature of the cup and its contents if the aluminum cup is replaced with one of equal mass made from silver. Please include work so I can understand. Thank you!
We know that,
The method of mixture is given by,
Heat gained by the ice = Heat lost by the water + Heat lost by the cup



A 32.6-g ice cube at 0 °C is added to 125 g of water in a 63.1-g aluminum cup. The cup and the water have an initial temperature of 23.3 °C. Calculate the equilibrium temperature of the cup and its contents. Do not enter unit. Calculate the equilibrium temperature of the cup and its contents if the aluminum cup is replaced with one of equal mass made from silver. Do not enter unit.
A 33.3-g ice cube at 0 °C is added to 126 g of water in a 62.5-g aluminum cup. The cup and the water have an initial temperature of 24.3 °C. Calculate the equilibrium temperature of the cup and its contents. Do not enter unit. Calculate the equilibrium temperature of the cup and its contents if the aluminum cup is replaced with one of equal mass made from copper. Do not enter unit.
A 33.7 g ice cube at 0 0C is added to 126 g of water in a 64 g aluminum cup. The cup and thewater have an initial temperature of 24 0C. a) Find the equilibrium temperature of the cup and its contents b)calculate the equilibrium temprature of the cup and its contents if the aluminum cup is replaced with one of equal mass made from copper do not enter unit
A. A 32.1 g of ice at 0 C is added to 120g of water in a 64.8 g aluminum cup. the cup and the water have an initial temperature of 23.7 C. Calculate the equilibrium temperature of the cup and its contents. B. Calculate the equilibrium temperature of the cup and its contents if the aluminum cup is replaced with one of equal mass made from glass.
An ice cube at 0°C was dropped into 30.0 g of water in a cup at 45°C. At the instant all of the ice is melted, the temperature of the water in the cup was 19°C. How many moles of ice was the ice cube? What was the mass of the ice cube? ANSWER, moles: mol ANSWER, grams: 1 g Check
An ice cube of mass 8.5 g at temperature 0∘C is added to a cup of coffee, whose temperature is 90 ∘C and which contains 130 g of liquid. Assume the specific heat capacity of the coffee is the same as that of water. The heat of fusion of ice (the heat associated with ice melting) is 6.0 kJ/mol. Find the temperature of the coffee after the ice melts.(in C)
A 20.64 g ice cube at -1.93 oC is place in an aluminum cup whose initial temperature is 137.9 oC. The system comes to an equilibrium temperature of 17.96 oC. What is the mass in grams of the cup? The specific heat of ice is 2.093 J/g oC and that of aluminum is 0.901 J/g oC.
A 250 g ice cube at -10∘C is placed in an aluminum cup whose initial temperature is 70∘C. The system comes to an equilibrium temperature of 20∘C.
We have a closed system with an aluminum cup, water and a cube of ice. The glass has a mass of 100 grams. The temperature of the glass and water is 20 degrees C. We also have 200 grams of water in total. The cube of ice weighs 5 grams and is at 0 degrees C. Find the equilibrium temperature of the system.
An ice cube with a mass of 46.4 g at 0.0 ∘C is added to a glass containing 4.20×102 g of water at 45.0 ∘C . Determine the final temperature of the system at equilibrium. The specific heat capacity of water, ?s , is 4.184 J/g⋅∘C , and the standard enthalpy of fusion, Δ?∘fus , of water is 6.01×103 J/mol . Assume that no energy is transferred to or from the surroundings.