Question

Chem 1212 Lab Manual 0.1 MZASO. and unknown CuSO, code and potential 29999999 Unknown concentration of CuSO. ) (Use observed potential for the 2 Z I MICO.IM/Cu cell as the the number of ficant figures in the in the calculation and Procedure 11.pl meter ( chain log cH01 1.2897 pH of Buffer mV reading Volts 11. 0 284.7 12.0 240.3 1.2693 3.0 202.8 1.2028 11873.6813 156.0 1.056 117.0 1.017 T2043 1-87.5 Foals - 127.7 21277 16 -1834 -1231 -10 Doom tem Record the temperature of the room 100 ! Efficiency of Calibrated pH meter (divide by 100, if efficiency given in percent) (4 ) Slope of graph of buffer voltage as a function of logio [H0') Slope above divided by the pH meter efficiency

Answer 1

Following is the - complete Answer -&- Explanation: for the given: Question: in...typed & image format...

$\Rightarrow$Answer:

1. Slope of the graph of the buffer voltage, as a function of log₁₀[H₃O⁺ ] = 0.053  
2. Above: Slope: divided by the pH meter efficiency = 0.00053  

​​​​​​​$\Rightarrow$Explanation:

• Given:

1. ​​​​​​​Efficiency of the pH meter = 100.0 %
2. Following data table: prepared by using MS Excel, presented here in...image format...

​​​​​​​
Buffer voltage (Volts) log10[H3O+] 0.2847 0.26931 0.2028 0.0873 0.056 0.017 -0.043 -0.0875 -0.1277 -0.1834

• Step - 1:

​​​​​​​Based on the above: data table: we can form the following buffer voltage ( volts ) vs. log₁₀ [H₃O⁺ ] : graph: prepared by using MS Excel, presented here in: image format...

Buffer voltage vs. log10[H3O+] graph y = 0.053x + 0.343 buffer voltage ( volts ) + Buffer voltage vs. log10[H3O+] graph — Linear (Buffer voltage vs. log10[H3O+] graph) NH HOH is log10[H3O+]

$\Rightarrow$Equation of the linear trendline: y = 0.053 x + 0.343   ------------------------Equation - 1

$\Rightarrow$Where:

1. x - axis denotes: the values of Log₁₀ [H₃O⁺ ]
2. y - axis denotes:  the values of  buffer voltage ( in volts )
3. slope = 0.053  

• ​​​​​​​Step - 2:

​​​​​​​Therefore: as we can see, above:

$\Rightarrow$Slope of the graph of the buffer voltage, as a function of log₁₀[H₃O⁺ ] = 0.053  

$\Rightarrow$ Slope: divided by the pH meter efficiency = ( 0.053 ) / ( 100.0 ) = 0.00053