Question

is the 6-15 ce is How many moles of specified particles are present in a sample of each of the following substances if each sample weighs 5.00 g? a. CO molecules b. CO, molecules ce is

Answer 1

The solution is given in image below.

No. of moles a Criven Mass Molar Mass - 289 (a) triven Mars of 10 = 5g Molar Mars of to = 12 +16 o = 289 No. of moles of 10 = s os = 0.178 mdes 16) Given Mars of co₂ = 5g Molar Mans - 12 + 2X16 = 12 +32 = 44g No. of moles of co₂ = 2 h = 0.115 moles (c) Criven Mars of Butto = 5g Molar Mans of Butto = 4x9 + 10x1 = 36 +0 =H6 a No. of moles of Buttio = 3 4 5 = 0.108 moles (6-17) The formula mans of a compound whore molas mans is 44.00 g is CO2 (Q2 = 12:011 + 2x15.999 - 12.011 + 3).998 = 44.009 = 44. Olg

(9) No. of moles of H₂SO3 = 2 I mole of H2SO3 contain no. of - moles of o=3 .: 2 moles of H₂SOz will contain no. of moles go=16 (6) No. of moles of H2S 072 "I mole of H₂S2O7 contain no. of moles go=7 - 2 mole of H₂S2O7 will contains no. y moles of 0 = 2x2 (C) No of moles of soul, =2 * 1 mole of sour contains no of moles of o=1 .. 2 moles of sou will condain no- g moles of O = 1X2 a 287 (9) No. of moles of so, 42 = 2 - 1 mde og sąuz contains no. of moes goe2 .. 2 mole of SO₂ U will contain no. y maes go = 2x2 - 9