Question

Thermo: Volume Expansion - liquid in cup

Content LIQUIDS SOLIDS Material Material (°C)1 (°C)-1 Aluminum 75 x 105 Acetone 1430 x 10-6 1250 x 106 Bismuth 39.5 x 10-5 Benzene 56 x 10-5 1100 10- Brass Bromine Concrete 36x 10-6 Ethyl alcohal 1090 x 10-6 50 x 10 Gasoline 950 10 Copper 55.8x 10 Galena 500 10 Glycerin 27.6 10 990 x 106 Glass Kerosene Gold Mercury 180 x 10 42 x 10 Olive oi 35 x 105 700 x 10 Iron Lead 87 x 10-5 Petroleum 1000 x 10-6 Nickel 39 x 10-5 Toluene 1080 x 10-6 58.3 x 10 214 x 10- Silver Water E Problem A container made of gold is filled to the brim (and is in thermal equilibrium) with 476 mL of mercury at 19°C. The temperature of both is then increased to 96 C. For this temperature, determine the volume of the mercury and what fraction of the mercury spilled out of the container. Volume of mercury at 96"C Fraction of mercury that spilled

Answer 1

t; = 19°c ta=96°c. B mi = 180x10-6 ßg = 42x10-6 v=476 ml. -> final volume of mercury = YEV + ubat =476+ 476x 180x10-6x96-19) = 482.597me - volume of mercury spilled => V Bm At - VBg A+ = VA(Pm-B3) = 476 x 77 x 180-427x10-6 1- 5.058 me of mercury is spitted-