Question

How many grams of solute are present in 515 mL of 0.610 M KBr? mass of solute:
How many moles of K, Cro, are in 86.45 g K, Cro? 86.45 g K, Cro, = mol K, CrO How many moles of CaC,0,H,O are in 130.2 mg CaC
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Answer #1

KBY Mat = \19 Smo molaity mass ooo Volue (m) M at Solu ma = O61 o x 19 X515 mass 37. 39 K2C04 mol mass = 194 1 gmd moles o 0

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