Question

over the 11. In the reaction CLC) + 3F18) -- 2 CIF), if the average rate first 6.00 s, how much CIF, will form during this time S 2CFL the d ance of F, Fis 0250 -0.250 0.750 M b. 1.00 d. 2.00 M 1.50 M 3.00 M 12. Given the following data in the der of the reaction with respe 2 NO(g) ) - 2 NOCIS) Experiment INOT (M) 0.0300 0.0150 ICI (M) 0.0100 0.0100 0.0-400 Rate (M ) 3.4 10 8. 5 10 3.4 * 10+ 0.0150 a. first b. second d. e fourth zero c. third 13. Given the following date determine the order of the reaction with respect to H. He) +2 ICIC) - 1,6) +2 HCI) Experiment Hl (torr) FICIJ (tor) Rate (M) 250 325 1.34 0331 325 0.266 250 a one-half b. second c. first d. third c. three-halves the partial order with '14. For the rate law Rate respect to B is A B ), the partial order with respect to A is ... and the total order is e. The orders cannot be determined without a chemical reaction. 15. A second-order reaction (2 A ÆB) with a rate constant of 0.350 M's is found to have a half-life of 3.45 s. What was the initial concentration of the reactant, [A]o? a. 0.828 M d. 1.21 M b. 0.201 M e. 0.350 M c. 1.00 M 16. Nitrogen dioxide undergoes thermal decomposition according to the second-order reaction 2 NO,(g) - NO(g) +0,(8). When 0.500 M NO, is allowed to react for 90.0 seconds, its concentration to 0.0196 M. What is the half-life of the reaction when [NO2] = 0.500 M? a. 0.273 8 d. 3.40 s b. 1.27 s e. 86.6 s c. 3.67 s

Answer 1

Co-250) X6 150 M (12 KCNO? Ceb Rate 3-4nioK CO03)% o-00-0 K -K 3.4 2 = 2 O85 8-5x0.1 3.4 t No-2 13 ale 1-34= K C250% (325) 0331= K (250)x (81) 0-266- K(50)x C325) 1.39 0331 ५ ৫०) = 9=) 325 (2 1 1.34 0266 525 Order w.r.t H = 57 ) wrt Az (4 w.r.t B1 2.