Question

The RCL series circuit shown below (R=0.04 2, L=5.00uH) is in resonance with a source that has a frequency of 2000 Hz and a 12.0-V ims potential. a.) what is the capacitance of the circuit? for parts (6)-(f), the circuit is now driven with the same potential but with a frequency of 1700th. b.) Determine the phase angle Ø between the potential across the RCL circuit and the current induced by the AC source, which leads the current or potential? (.) Draw V, Vc, VR, and V in the phasor diagram d.) Determine the rms energy stored in the capacitor and the rms energy stored in the inductor ei) what is the power supplied to the circuit f.) What is the power dissipated by the resistor?

Answer 1

Here we apply concept of series RLC circuit with AC supply. We apply phasor diagram concept to solve the circuit.

hi elut R = 0.042 L=5.00uH c=2 Resonance frequency to = 2000 Hz - vous pourre = 12:0 volti We know, at resonance X - Xe تعطيككل2 = XL = t = f = 2 5C 2000 Hz – I - 25 √( S106 H) C E c = 6.3326 X10-9 fard SX16-6 =1C = 1:266 x 10-3 farad| 16Nove f = 1700 Hz X = 2,5 L = 21 (1900)(5x169 29 - X0·0534r _X_la - 21fC 24(1700) (1.266x103) C = X = 0.03395 . As Xe> X Vo = I x Va I X » Ve > V In capacitor, current leade voltage by goo to e lage go by I 11 ŽR t

leads I by goo Xeos >$-tan 6:0739 0.04 o = 27.20 As ve v Lo Visource will be belowe I .. current leade voltage by 27, 20 shade angle ths 27.2° - (3) In Inductor, U = I l 1 2 on Iyms = Vrms - 12 volt - CR3+ (X-XI)? Tyme = 12 Volt 10:04)2+60-07395-0-053472 R Toms = 266-844 Amp so Una (5X106) 266:844) J u = 0.178 Toile.

Capacitor in stored Energy Ue = كاراكل =ع - 1 ( 6 . 61265) (844 266XI69X366) = 0د - له کے گ 0 . 246 = 0 2