Question

14. Oakton Manufacturing makes two types of rocking chairs specifically designed for men and women known as the His and Hers models. Each chair requires four legs and two rockers but differing numbers of wooden dowels. Each His chair requires four short dowels and eight long dowels while each Hers chair requires eight short dowels and four long dowels. Each His chair contributes $10 in profit while each Hers chair contributes $12. The company has 900 legs, 400 rockers, 1200 short dow- els, and 1056 long dowels available. The company wants to maximize its profit while also ensuring that it makes at least half as many His chairs as Hers chairs. a. Formulate an LP model for this problem. b. Sketch the feasible region for this problem. c. Find the optimal solution.

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Ans! Let us denote 4hat the opt audti given on each Rs cais and Prop O o ea f $i2 on each ers chaPs model en Maxi m2e Aso, e ud le tolal ach chaiy needs four legs numbex of es evalable e companys 00 the constant f ts model is : So one And, each chaY needs too Yeckers and-) the total nuwbex of Yockes avalable in the campay ne ef the constain mde 2x1+2x2 스4002 し1200 uXIt 212 hnd, each clai a dowels Heys ckat neds frdeels de toh umber chest daels lable nmpor ts mde a) on the basis above stucture , the 1 p mode Jeven 2.3 subject to un, tux2纟900. cens.dex Hhe cons case(.): scaving as shouobeloo bainste equal to the equaton LtX, t»,-1200 . ux,belouw on Put憫.xlso. 8시 : 1056 . x = 132. on puting.YO их 2-1056. 2 16H | | 132 | ease (3): Solvryhe equalen 찌t2x2:400, as shown below 2x 1 t 2x2 = 400 on putting 50 y2=2.QDin abulax 0O 2. case (H) ; Solv;n9the equation 니지 +ux229CO, as shon belou 리지: 90C . xに225. ux正9co. Ym 22S6 case (s): selving the equaton 12- o, as shown belou: onputta9, I-O puting, x 2. And O on 3By plotting the values of the 5 cases on the graph, the following graph is obtained X, 8x, + 4x2 = 1056 250 200 4x1 + 4x2 = 900 150 Optimal solution: xǐ Profit $2,104 76, x,-112 100 4x, +8x2 -1200 5아 50 100 50 200 250 300 After plotting all the equations on the graph, it can be seen from the graph that the region in the dark is the feasible region.7he optimal solution can be seen the gtq MAXX1 +122 Hence, he opimal solohioh gives

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