When 0.231G of phosphorus reacts with chlorine to form phosphorus trichloride, in a coffee-cup calorimeter of heat capacity 216J/C, the temperature of the calorimeter rises by 11.06C.
a)Provide a thermochemical equation
b) Give the Enthalpy change, Change of H, for the reaction
a) Thermal equation: 2P(s) + 3 Cl2(g) ----> 2PCl3(l) ; DHrxn = -641.34 KJ
b) No of mol of phosphorus reacted = 0.231/31 = 0.00745 mol
heat released(q) = C*DT
C = heat capacity = 216J/C
DT = 11.06 C
q = 216*11.06 = 2389 joule
q = 2.389 kj
DHrxn = -2.389/0.00745 = -320.67 kj/mol
DHrxn =-320.67*2 = -641.34 kj
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