Question

Use the References to arcess important valnes if needed for this question. Furnace H,0 absorber CO absorber Sample A 13.89 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 19.70 grams of CO2 and 12.10 grams of H2O are produced In a separate experiment, the molar mass is found to be 62.07 gmol. Determine the empirical formula and the molecular formula of the organic compound Enter the elements in the order C. H, O empirical formula- molecular formula- Previous Next

Answer 1

CxHyOz + O2 13 899 . . . CO2 + H2O . 45409 г)2-104 First we Convert gram value into the mole 19. 7090x = 0.44 mol co mol co2 ччя со 2, 12: JoЯ Н20 у . б. 6+mo) H2O то) Н20 189 120

co -> 0.44 molc |H2O --> 0.67 mol X2' = 1.34moll_ so 0.4umolc X olundson rolunglon - 12gc 5:28 g C molc rolusolen im olursat SON - 1:34 mot H x latte = 1:349 H - Imoly then we Calculate gram of oxygen in the Sample- На Косіб). Oxygen = 13.89 - 5.28g - 1:34g = 7.27g of oxygen- 7.278 O X Imolo = 0.45 molo 1680 Compound mol. 0.444 0:45 L .34 mol 0.45 mol Then we find out the mol Hydrogen and Oxygen. 6 = 0.45 mol 0.45mo ratio between Carbon,

H = 1.34 mol g 0.45 mol 2 g mola 3.0 molit Lo= 0.45mol = 1 Allan 0.45 mo) so the emperical formula is - CH₂O ?? У А др.) Molecular formula = Molecular formula Mass Emprical formula Mass - H! X H B 82.07. - 31 D = 21 So the Molecular formula is - CH₃OX 2 = C24602