velocity of bob just before hitting box
u^2 = 2 gh = 2* 9.8 * 1
u = 4.427 m/s
velocity of box just after elastic collision
v = 2 m u / ( m + M) = 2* 10* 4.427 / ( 10 + 2)
v = 7.379 m/s
using conservation of energy
mg h + u mg d = 0.5 m v^2
9.8* d sin 40 + 0.6* 9.8* d = 0.5 * 7.379^2
d = 2.235 m
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Comment before rate in case any doubt, will reply for sure.. goodluck
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